Solubility of calcium phosphate (molecular mass, `M`) in water is `W g` per `100 mL` at `25^(@)C`. Its solubility product at `25^(@)C` will be approximately

Options

A. `10^(9)((W)/(M))^(5)`
B. `10^(7)((W)/(M))^(5)`
C. `10^(5)((W)/(M))^(5)`
D. `10^(3)((W)/(M))^(5)`

Answer

B

Explanation

Solubility `S=(10W)/(M) ("mol")/("lit")`
`K_(sp) " of " Ca_(3)(PO_(4))_(2) =108 S^(5)`
`=108 xx 10^(5) ((W)/(M))^(5)`