Periodic acid splits glucose and fructose into formaldehyde and formic acid, Ratio of moles of formic acid in glucose and fructose is

Options

A. `1:2`
B. `5:3`
C. `1:1`
D. `2:3`

Answer

B

Explanation

`CHO-CHOH-underset("glu cos e")(CHOH)-CHOH-CHOH-CH_(2)OH`
`overset(5HIO_(4))(to) 5HCOOH+HCHO+5HIO_(3)`
`CH_(2)OH-overset(O)overset(||)C-underset("fructyose")(CHOH)-CHOH-CHOH-CH_(2)OH`
`overset(5HIO_(4))(to)3HCOOH+2HCHO+5HIO_(3)+CO_(2)+H_(2)O`
`:.` molar ratio is 5:3