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The ratio of 11^(th) term from the begin...

The ratio of `11^(th)` term from the beginning and `11^(th)` term the end in the expansion of `(2x-(1)/(x^(2)))^(25) " is " -`

A

`x^(15)`

B

`-2^(5) x^(15)`

C

`2^(15)x^(5)`

D

`2^(5)x^(-15)`

Text Solution

Verified by Experts

The correct Answer is:
B
`T_(11"staring") =25 C_(10) 2^(15)((1)/(x^(5)))`
`T_(11"ending") = T_(16("starting"))`
`=-.^(25)C_(15)2^(10)((1)/(x^(20)))`
`"then" (T_(11("starting")))/(T_(11("ending")))=-2^(5) x^(15)`
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