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"if y"="cos"^(-1)((5"cos" x-12 "sin"x)/(...

`"if y"="cos"^(-1)((5"cos" x-12 "sin"x)/(13)),` where
`x in (0,(pi)/(2)) , " then "(dy)/(dx) " is"-`

A

1

B

-1

C

0

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`y = " cos"^(-1) [(5)/(13) " cos " x - (12)/(13) " sin "x]`
`y = " cos"^(-1) underset("cos"alpha)underset(darr)([(5)/(13))) " cos " x - underset("sin"alpha)underset(darr)((12)/(13)) " sin "x"]"`
`="cos"^(-1) ["cos"(x+alpha)]`
`y= x+alpha " "y^(1) =1`
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