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The points (1,1), (0, "sec"^(2) 0), ("co...

The points `(1,1), (0, "sec"^(2) 0), ("cosec"^(2) 0,0 )` are collinear for-

A

`0=(pi)/(2)`

B

`0ne (npi)/(2)`

C

`0=npi`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`|{:(1,1,1),(0,sec^(2)theta,1),(cosec^(2)theta,0,1):}|`
`rArr "sec"^(2) 0+ "cosec"^(2)0 -"sec" ^(2)0"cosec"^(2)0 =0`
`rArr ("sin"^(2)0+"cos"^(2)0-1)/("cos"^(2)0"sin"^(2)0) =0`
Which is ture if sin0 cos0`ne 0`
`0 ne (npi)/(2)`
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