Given `A=[(1,1,1),(2,4,1),(2,3,1)], B=[(2,3),(3,4)].` Find P such that BPA= `[(1,0,1),(0,1,0)]`

Options

A. `|{:(-4," "7,-7),(" "3,-5," "5):}|`
B. `|{:(7,4,-7),(5,3,-5):}|`
C. `|{:(-7,7,-4),(" "3,5,-5):}|`
D. `|{:(-4," "7," "7),(" "5,-5," "3):}|`

Answer

A

Explanation

Here |A| = -1, |B| = -1
Now BPA `= [{:(1,0,1),(0,1,0):}]`
So, `B^(-1) BP A A^(-1) = B^(-1)[{:(1,0,1),(0,1,0):}]A^(-1)`
IPI `=(-1)((-1))/(I)[{:(" "4,-3),(-3," "2):}][{:(1,0,1),(0,1,0):}]`
`[{:(" "1," "2,-3),(" "0,-1," "1),(-2,-1," "2):}]`
`P=[{:(-4," "7,-7),(" "3,-5," "5):}]`