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The electric field at centre O, due to ...

The electric field at centre O, due to the segment of a ring of liner change density `8 C//cm` is -

A

`9 xx 10^(13)V//m`

B

`16 xx 10^(13)V//m`

C

`8 xx 10^(13)V//m`

D

`18 xx 10^(13)V//m`

Text Solution

Verified by Experts

The correct Answer is:
4
`E =(lambda)/(2pi epsi_(0)r) sin.(theta)/(2)`
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Knowledge Check

  • Magnetic field at the centre O due to the given structure is

    A
    `(mu_(0)I)/(4R)[3/2]o.`
    B
    `mu_(0)I/(2R)[3]ox`
    C
    `(mu_(0)I)/(4R)[3/2]ox`
    D
    `(mu_(0)I)/(4R)[3]o.`

  • Magnetic field at the centre O due to the given structure is

    A
    `(mu_(0)I)/(4R)[3/2+1/pi]ox`
    B
    `(mu_(0)I)/(2R)[3+1/(pi)]ox`
    C
    `(mu_(0)I)/(4R)[3/2]ox`
    D
    `(mu_(0)I)/(4R)[3+2/pi]o.`

  • The electric field at the centre of a uniformly charged ring is zero. What is the electric field and potential at the centre of a half ring if the charge on it be Q and its radius be R ?

    A
    `(1)/(4 pi epsilon_(0)) (Q)/(pi R^(2)) ,(1)/(4 pi epsilon_(0)) (Q)/(pi R)`
    B
    `(1)/(4 pi epsilon_(0)) (Q)/(R^(2)) ,(1)/(4 pi epsilon_(0)) (2Q)/(pi R)`
    C
    `(1)/(4 pi epsilon_(0)) (2Q)/(pi R^(2)) ,(1)/(4 pi epsilon_(0)) (Q)/(R)`
    D
    `(1)/(4 pi epsilon_(0)) (2Q)/( R^(2)) ,(1)/(4 pi epsilon_(0)) (3Q)/(pi R)`

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