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In given circuit, switch S is closed ...

In given circuit, switch S is closed at t=0 . The charge on the capacitor ar steady state will be

A

`(Cepsi R_(1))/(r +R_(1))`

B

`(Cepsi R_(2))/(r +R_(2))`

C

`(Cepsi R_(2))/(r +R_(1))`

D

`(Cepsi R_(1))/(r +R_(2))`

Text Solution

Verified by Experts

The correct Answer is:
2

`i = (epsi)/(r+ R_(2))`
`C_(V) + V_(R1)= iR_(2)`
`V_(C) = (epsiR_(2))/(r +R_(2))`
`q = CV_(c) =(CepsiR_(2))/(r + R_(2))`
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