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In the nuclear raction .1H^2 +.1H^2 rarr...

In the nuclear raction `._1H^2 +._1H^2 rarr ._2He^3 +._0n^1` if the mass of the deuterium atom `=2.014741 am u`, mass of `._2He^3` atom `=3.016977 am u`, and mass of neutron `=1.008987 am u`, then the `Q` value of the reaction is nearly .

A

0.000352MeV

B

3.27 MeV

C

0.82 MeV

D

2.45 Me V

Text Solution

Verified by Experts

The correct Answer is:
B
`Q=[sum m_("reac tan ts")-summ_("products")]c^(2)`
`=2xx2.014741-(3.016977+1.008987)xx931MeV`
`=3.27Me V`
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