A homogenous block of mass m, width b and height h is resting on a rough horizontal surface A horizontal force F is applied to it , which makes it to move with a constant velocity . The coefficient of friction between block and surface is `mu` Find the greatest height at which force F may be applied to slide the block with out tipping over

Options

A. `(b)/(2 mu)`
B. `(2b)/(mu)`
C. `(b)/(mu)`
D. `(2 sqrt(2b))/(mu)`

Answer

A

Explanation

`sum fy impliesN=mg`
`sumfx=f-F=0`
woth out toppling
`sumtau_(A)=0`
`fh+mg ((b)/(2))`
`h=(b)/(2mu)`