A pearl of mass m is in a position to slide over a smooth wire .At the intial instant the pearl is in the middle of the wire ,The wire moves linerly in a horizontal plane with an with the acceleration of the pearl Q.r.t wire is -

Options

A. `g sin theta - a cos theta`
B. `g sin theta - g cos theta`
C. `g sin theta - a cos theta`
D. `g cos theta + a sin theta`

Answer

A

Explanation

net acceleration of perarl
in y direction net force is zero .
in X direction `a' = sin theta -a cos theta`