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A charge q is placed at the centre of th...

A charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium if q is equal to:

A

`-(Q)/(2)`

B

`-(Q)/(4)`

C

`-4Q`

D

`+(Q)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`F = (kQq)/((r)/(2))^(2) +(kQ Q)/(r^(2)) = 0`
`q =- (Q)/(4)`
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