The electric field intensity due to a thin infinity long straight wire of uniform linear charge density `lambda` at O is-

Options

A. `(lambda)/(2pi epsilon_(0)R)`
B. `(lambda sqrt(2))/(2pi epsilon_(0)R)`
C. `(lambda sqrt(5))/(2pi epsilon_(0)R)`
D. zero

Answer

A

Explanation

`E_(arc) = (2k lambda)/(r) sin.(theta)/(2)`
`=(2k lambda)/(r) sin.(180^(@))/(2)`
`= (lambda)/(2pi epsilon_(0)R)`