Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is-

Options

A. `10sqrt(2)V//m` at `45^(@)` with x-axis
B. `10sqrt(2)V//m` at `135^(@)` with x-axis
C. `5sqrt(2)V//m` at `45^(@)` with x-axis
D. `5sqrt(2)V//m` at `135^(@)` with x-axis

Answer

A

Explanation

`E = (Deltav)/(Delta r) = (10)/(1 cos 45^(@)) = 10 sqrt(2)`

at `45^(@)` with 'x' axis because electric field should be perpendicular to equipotential surface and directed form high potential to low potential