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Charge on an originally uncharged conduc...

Charge on an originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in figure. Assume that the induced negative charge on the conductor is equal to the positive charge q on the rod. Then the flux through surface `S_1` is

A

zero

B

`q//epsilon_(0)`

C

`-e//epsilon_(0)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`phi = (q_("in"))/(epsilon_(0))`
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