An object is approaching a fixed plane mirror with velocity `5ms^(-1)` making an angle of `45^(@)` with the normal. The speed of image w.r.t. the mirror is

Options

A. `5m//s`
B. `(5)/(sqrt(2))m//s`
C. `5sqrt(2)m//s`
D. `10m//s`

Answer

C

Explanation

`vec(v)_(O) = (5)/(sqrt(2)) hati +(5)/(sqrt(2)) hatj`
`vec(v)_(I) =- (5)/(sqrt(2)) hati +(5)/(sqrt(2)) hatj`
`vec(v)_(I//O) =- (10)/(sqrt(2))hati, |vec(V)_(I//O)| = 5sqrt(2)m//s`