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In a Young's double-slit experiment, let...

In a Young's double-slit experiment, let `S_(1)` and `S_(2)` be the two slits, and `C` be the centre of the screen. If `/_S_(1)CS_(2)=theta` and `lambda` is wavelength, the fringe width will be

A

`(lambda)/(theta)`

B

`lambda theta`

C

`(2lambda)/(theta)`

D

`(lambda)/(2theta)`

Text Solution

Verified by Experts

The correct Answer is:
A

`D theta = d`
`beta = (lambdaD)/(d) = (lambdaD)/(D theta) = (lambda)/(theta)`
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