If ratio of maximum to minimum intensity...

If ratio of maximum to minimum intensity in an interference experiment is 16:1 then ratio of amplitudes of individual waves is-

`4:1`

`16:1`

`5:3`

`25:9`

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The correct Answer is:

`(I_(max))/(I_("min")) = 16`
`(sqrt(I_(1))+sqrt(I_(2)))/(sqrt(I_(1))-sqrt(I_(2))) =4`
`sqrt(I_(1)) +sqrt(I_(2)) = 4sqrt(I_(1)) -4sqrt(I_(2))`
`3sqrt(I_(1)) = 5sqrt(I_(2))`
`(sqrt(I_(1)))/(sqrt(I_(2))) = (5)/(3)=(A_(1))/(A_(2))`

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