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If the wavelength of photon emitted due ...

If the wavelength of photon emitted due to transition of electron from third orbit to first orbit in a hydrogen atom is `lambda` then the wavelength of photon emitted due to transition of electron from fourth orbit to second orbit will be

A

`(128)/(27)lambda`

B

`(25)/(9)lambda`

C

`(36)/(7)lambda`

D

`(125)/(11)lambda`

Text Solution

Verified by Experts

The correct Answer is:
A
`13.6 z^(2) ((1)/(1^(2))-(1)/(3^(2))) =(hc)/(lambda)`
`13.6z^(2) ((1)/(2^(2))-(1)/(4^(2))) = (hc)/(lambda_(1))`
On division, `((8)/(9))/((3)/(16)) = (lambda_(1))/(lambda)`
`:. lambda_(1) = (128)/(27)lambda`
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Wavelength of the photon emitted as a result of electronic transition from the third orbit to the first orbit in a hydrogen atom is lamda and the wavelength of the photon emitted as a result of electronic transition from the fourth orbit to the second orbit is given as N times lamda . Find the value of N.

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Knowledge Check

  • The transition of an electron from a 4s orbital to ls orbital in hydrogen atom causes

    A
    photoelectric effect
    B
    a Lyman line
    C
    increase in kinetic energy of electron
    D
    conversion of `H^+` to H atom

  • The vale of wavelength radiation emitted due to transition of electrons from n=4 to n=2 state in hydrogen atom will be

    A
    `(5R)/(36)`
    B
    `(16)/(3R)`
    C
    `(36)/(5R)`
    D
    `(3R)/(16)`.

  • The wavelength of light emitted from second orbit to first orbits in a hydrogen atom is

    A
    `1.215 xx 10^(-7)m`
    B
    `1.215 xx 10^(-5) m`
    C
    `1.215 xx 10^(-4) m`
    D
    `1.215 xx 10^(-3) m`

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