In semiconductor the concentrations of electron and holes are `8xx10^(18)//m^(3)` and `5xx10^(18)//m` respectively. If the mobilities of electrons and hole are `2.3 m^(2)//`volt-sec and `0.01m^(2)//` volt-sec respectively, then semicondutor is

Options

A. n-type and its resistivity is `0.34 Omega-m`
B. p-type and its resistivity is `0.034 Omega-m`
C. n-type and its resistivity is `0.034 Omega-m`
D. p-type and its resistivity is `3.4 Omega-m`

Answer

A

Explanation

`n_(e) gt gt gt n_(h)`
`:. N` type semiconductor
`P = (1)/(e[mu_(h)n_(h)+mu_(e)n_(e)])`
`= (1)/(1.6xx 10^(-19)[2.3xx8xx10^(18)+0.01xx5xx10^(18)])`
`= (1)/(0.16[18.4+0.05]) = (1)/(0.16 xx 18.45)`
`= (1)/(520) = 0.34 Omega - m`