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If alpha=0.98 and current through emitte...

If `alpha=0.98` and current through emitter `i_(e)=20 mA`, the value of `beta` is

A

4.9

B

49

C

96

D

9.6

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha = (I_(C))/(I_(E)) rArr I_(C) = alpha I_(E)`
`I_(B) = I_(E) - I_(C)`
`beta = (I_(C))/(I_(B))`
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