`(x^2-2x+1)xx(x^2-2x-3)`

If x≠ − 1 , 2 and 5, then the simplified value of {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} is equal to: यदि x≠ − 1 , 2 और 5 है तो {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} का सरलीकृत मान बराबर हैः

If x ne -1,2 and 5, then the simplified value of {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) is equal to : यदि x ne -1,2 और 5 है, तो {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) का सरलीकृत मान क्या होगा ?

Simplify : ((x^(2)-1)/((x^(2)-3x+2)))xx((x-2)/(x+1))

Express the following in the lowest terms. ((2x^(2)+1)/(x-1)+(x-1)/(x+1))xx((x^(2)-1)/(2x)):

Find each of the following products : (x^(3) - 5x^(2) + 3x + 1) xx (x^(2) - 3)

If y = (x-3) (x-2) (x-1) xx(x+1)(x+2) (x+3), then (d ^(2)y)/(dx ^(2)) at x=1 is:

solve for x,4^(x-1)xx(0.5)^(3-2x)=((1)/(8))^(-x)