" Q.7The velocity of a body moving in a straight line is given by "v=(3x^(2)+x)" m/s.Find accelerationat "x=2m

The velocity of a body moving in a straight line is given by v=(3x^(2)+x)m//s . Find acceleration at x=2m .

A partical is moving in a straight line such that ita velocity is given by v=t^(4)+3t^(2)+8 m//s . Find acceleration at time t=1 s .

The velocity function of an object moving along a straight line is given by v(t)=At^(2)+Bt . If at t=2s, the velocity is 3 m/s and acceleration is 0.500 m//s^(2) , find the value of the constant A.

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The position of a particle moving in a straight line is given by x=3t^(3)-18t^(2)+36t Here, x is in m and t in second. Then

The velocity v of moving object varies with displacement u as v=3x^(2)-2 ,then the acceleration at x=2m is

The velocity-position graph of a particle moving in a straight line along x-axis is given below. Acceleration of particle at x = 2 m is

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-