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If tan^(-1)(1/(1+1. 2))+tan^(-1)(1/1+2. ...

If `tan^(-1)(1/(1+1. 2))+tan^(-1)(1/1+2. 3)++tan^(-1)(1/(1+ndot(n+1)))=tan^(-1)theta,` then find the value of `thetadot`

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If tan^(-1)(1/(1+1. 2))+tan^(-1)(1/(1+2. 3))+.... +tan^(-1)(1/(1+n.(n+1)))=tan^(-1)theta, then find the value of thetadot

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tan(tan^(-1)((1)/(2))-tan^(-1)((1)/(3)))=

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