[" A non-stoichiometric compound "Fe_(7)S_(8)],[" consist of iron in both "Fe^(2+)" and "Fe^(+3)" form "],[" and sulphur is present as sulphide ions."],[" Calculate cation vacancies as a percentage "]

The non-stoichiometric compound Fe_0.94O is formed when some Fe^(+2) ions are replaced by Fe^(+3) ions. What is the percentage of Fe^(+3) ions in this ionic lattice ?

The non-stoichiometric compound Fe_0.94O is formed when some Fe^(+2) ions are replaced by Fe^(+3) ions. What is the percentage of Fe^(+3) ions in this ionic lattice ?

The non- stoichiometric compound Fe_(0.94)O is formed when x% of Fe^(2+) ions are replaced by as many 2//3 Fe^(3+) ions The value of x is:

The non- stoichiometric compound Fe_(0.94)O is formed when x% of Fe^(2+) ions are replaced by as many 2//3 Fe^(3+) ions The value of x is:

The non- stoichiometric compound Fe_(0.94)O is formed when x% of Fe^(2+) ions are replaced by as many 2//3 Fe^(3+) ions The value of x is:

A non-stoichiometric compound Cu_(1.8)S is formed due to incorporation of Cu^(2+) ions in the lattice of cuprous sulphide. What percentage of Cu^(2+) ions the total copper centent is present in the compound

The non - stoichiometric iron oxide has a composition Fe_(0.94) O . Find the ratio of ferrous and ferric ions present in it.