`10 C_ 5`

Evaluate: ^10C_5

Evaluate: "^10C_5

Evaluate the following : "^10C_4+ ^10C_5 .

""^10C_1 . ""^9C_5 + ""^10C_2. ""^9C_4 + ""^10C_3. ""^9C_3 + ""^10C_4. ""^9C_2 + ""^10C_5. ""^9C_1 + ""^10C_6 = ""^19C_6 + x then x =

""^10C_1 . ""^9C_5 + ""^10C_2. ""^9C_4 + ""^10C_3. ""^9C_3 + ""^10C_4. ""^9C_2 + ""^10C_5. ""^9C_1 + ""^10C_6 = ""^19C_6 + x then x =

Two charges of 5 * 10^-6 C and -5 * 10^-6 C are placed 5 cm apart, at points A and B respectively. Find the electric field at C, 5 cm away from both A and B.

A contest consists of pedicting the results (win, draw or defeat) of 10 foot ball matches. Then the number of ways n which one entry contains at least 6 icorrect results is (A) 3^10 - sum_(r=0) ^5 .^10C_r 2^r (B) 30^10-sum_(r=1)^5 .^10C_r 2^r (C) sum_(r=0)^5 .^10C_r (D) sum_(r=6)^5 .^10C_r 3^r

At a point due to a point charge, the value of electric field intensity and potential are 32 NC^(-1) and 16 JC^(-1) respectively. The magnitude of charge and distance from the charge from the point of observation are.....(a)8.89 × 10 − 10 C, 0.5 m (b)8.89 × 10 − 10 C, 2m (c)2 × 4.6 × 10 − 10 C (d)5 × 4.6 × 10 − 10 C

If "^10C_r = "^10C_(r+2) , then "^5C_r equals