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d/(dx)[tan^(-1)((sqrt(x)(3-x))/(1-3x))]=...

`d/(dx)[tan^(-1)((sqrt(x)(3-x))/(1-3x))]=` `1/(2(1+x)sqrt(x))` (b) `3/((1+x)sqrt(x))` `2/((1+x)sqrt(x))` (d) `3/(2(1+x)sqrt(x))`

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d/(dx)[tan^(-1)((sqrt(x)(3-x))/(1-3x))] is (a) 1/(2(1+x)sqrt(x)) (b) 3/((1+x)sqrt(x)) (c) 2/((1+x)sqrt(x)) (d) 3/(2(1+x)sqrt(x))

d/(dx)[tan^(-1)((sqrt(x)(3-x))/(1-3x))] is (a) 1/(2(1+x)sqrt(x)) (b) 3/((1+x)sqrt(x)) (c) 2/((1+x)sqrt(x)) (d) 3/(2(1+x)sqrt(x))

d/(dx)[tan^(-1)((sqrt(x)(3-x))/(1-3x))]= (a) 1/(2(1+x)sqrt(x)) (b) 3/((1+x)sqrt(x)) 2/((1+x)sqrt(x)) (d) 3/(2(1+x)sqrt(x))

(d)/(dx)[tan^-1((sqrt(1+x^(2))-1)/(x))]=

(d)/(dx)tan^(-1)((sqrt(x)-x)/(1+x^((3)/(2))))=

(d)/(dx)tan^(-1)((x)/(1-sqrt(1+x^(2))))]=

(d)/(dx)(tan^(-1)((x)/(sqrt(a^(2)-x^(2))))

(d)/(dx) {Tan ^(-1) ""(sqrt(1-x))/(1+ x) }=

d/dx(tan^-1(x/sqrt(a^2-x^2))=