" If "y(x)=int_(pi^(2)/16)^(x^(2))(cos x*cos sqrt(theta))/(1+sin^(2)sqrt(theta))d theta," then find "(dy)/(dx)" at "x=pi

If y(x)=int_((pi^(2))/(16))^(x^(2))(cos x cos sqrt(theta))/(1+sin^(2)sqrt(theta))d theta then find y'(pi)

If y(x)=int_((pi^(2))/(16))^(x^(2))(cos x cos sqrt(theta))/(1+sin^(2)sqrt(theta)), then f in d(dy)/(dx)atx=pi

If y(x)=\ int_(pi^2//16)^(x^2)(cos xdotcossqrt(theta))/(1+sin^2sqrt(theta))dotdtheta\ t h e n\ fin d(dy)/(dx)a t\ x=pi

If y(x)=int_(pi^2/16)^(x^2)(cosxcossqrt(theta))/(1+sin^2sqrt(theta))d theta , find (dy)/(dx) at x=pi .

If y(x)=int_(pi^2/16)^(x^2)(cosxcossqrt(theta))/(1+sin^2sqrt(theta))d theta , find (dy)/(dx) at x=pi .

If y(x)=int_(pi^2/16)^(x^2)(cosxcossqrt(theta))/(1+sin^2sqrt(theta)),then (dy)/(dx) at x=pidot is

If f(x)=int_((x^(2))/(16))^(x^(2))(sin x sin sqrt(theta))/(1+cos^(2)sqrt(theta))d theta, then find the value of f'((pi)/(2))^((16)/(16))

I f f(x)=int_((pi^2)/(16))^(x^2)(sinxsinsqrt(theta))/(1+cos^2sqrt(theta))d theta, then find_the value of f^(prime)(pi/2)dot

Iff(x)=int_((x^2)/(16))^(x^2)(sinxsinsqrt(theta))/(1+cos^2sqrt(theta))d theta, then find the value of f^(prime)(pi/2)dot

x=sqrt(sin2 theta),y=sqrt(cos2 theta) then find (dy)/(dx)