[" An object is projected with velocity "vec V_(0)=15hat i+20hat j" .Considering "x" along horizontal axis and "],[y" along vertical axis.Find its velocity after "2s" ."],[" Fake "g=10ms^(-2)" ] "]

An object is projected with velocity vecv_(0) = 15hati + 20hatj . Considering x along horizontal axis and y along vertical axis. Find its velocity after 2s.

An object is projected with velocity vecv_(0) = 15hatj + 20hatj . Considering x along horizontal axis and y along vertical axis. Find its velocity after 2s.

A body is projected from the ground with a velocity vec(v)= (3 hat(i) + 10 hat(j)) ms^(-1) . The maximum height attained and the range of the body respectively are (given g= 10 ms^(-2) )

A point object is moving with velocity v_(0) =2 hat(i) - 3 hat(j ) + 4hat( k) in front of a moving plane mirror whose normal is along x - axis.The mirror is moving with velocity v_(m) = hat(i) - 4 hat(j) + 2 hat( k ) . Find the velocity vector of image

A point object is moving with velocity v_(0) =2 hat(i) - 3 hat(j ) + 4hat( k) in front of a moving plane mirror whose normal is along x - axis.The mirror is moving with velocity v_(m) = hat(i) - 4 hat(j) + 2 hat( k ) . Find the velocity vector of image

At a height of 0.4 m from the ground, the velocity of projectile in vector from is vec(u)=(6hat(i)+2hat(j)) (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is : (g = 10 m//s^(2))

A light body is projected with a velocity (10hat(i)+20 hat(j)+20 hat(k)) ms^(-1) . Wind blows along X-axis with an acceleration of 2.5 ms^(2) . If Y-axis is vertical then the speed of particle after 2 second will be (g=10 ms^(2))

A light body is projected with a velocity (10hat(i)+20 hat(j)+20 hat(k)) ms^(-1) . Wind blows along X-axis with an acceleration of 2.5 ms^(2) . If Y-axis is vertical then the speed of particle after 2 second will be (g=10 ms^(2))