In equation `(Z - 1)^(n) = Z^(n) = 1 (AA n in N)` has solution, then n can be

If z_(1),z_(2),z_(3),…,z_(n-1) are the roots of the equation z^(n-1)+z^(n-2)+z^(n-3)+…+z+1=0 , where n in N, n gt 2 and omega is the cube root of unity, then

If z_(1),z_(2),z_(3),…,z_(n-1) are the roots of the equation z^(n-1)+z^(n-2)+z^(n-3)+…+z+1=0 , where n in N, n gt 2 and omega is the cube root of unity, then

{ n (n+1) (2n+1) : n in Z} sub

If n gt 1 and if z ^(n) = (z +1) ^(n) then :

If the equation |z(z+1)^(8)=z^(8)|z+1| where z in C and z(z+1)!=0 has distinct roots z_(1),z_(2),z_(3),...,z_(n).( where n in N) then which of the following is/are true?

Prove that none of the roots of the equation z^(n) = 2(1+ z+z^2 + …...+ z^(n-1)), n gt 1 , lies outside the circle |z|=3 .

On Z, define ox by (m ox n) = m^(n) + n^(m) : AA m, n in Z . Is ox binary on Z?

If z is a complex number satisfying z+z^(-1)=1 then z^(n)+z^(-n),n in N, has the value

if (2z-n)/(2z+n)=2i-1,n in N in N and IM(z)=10, then

if (2z-n)/(2z+n)=2i-1,n in N in N and IM(z)=10 , then