`2tan^(-1)(tan((7pi)/6))`

Let m be the number of solutions of sin(2x)+cos(2x)+cosx+1=0 in 0 lt x lt (pi)/(2) and n = sin [tan^(-1)(tan((7pi)/(6)))+cos^(-1)(cos((7pi)/(3)))] , then find the value of (m^(2)+n^(2)+m+n+4)

Find the value of : (1) sin^(-1)(sin.(5pi)/(6)) (2) cos^(-1)(cos.(13pi)/(6)) (3) tan^(-1)(tan.(7pi)/(6))

Find the value of the following: tan^(-1)(tan(7 pi)/(6))

tan^(-1)(tan^(5 pi/6))

tan^(-1)("tan"(7pi)/(5))

Find the value of tan^(-1)("tan"(7pi)/(6))+ cos^(-1)("cos"(7pi)/(6))

Evaluate each of the following: tan^(-1)((tan pi)/(3))( ii) tan^(-1)((tan(6 pi))/(7))( iii) tan^(-1)((tan(7 pi))/(6))

Find the value the following : tan^(-1) (tan. (7pi)/6)

tan^-1 (tan ((7π)/6))