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If sum(r=0)^(10)((r+2)/(r+1)).^n Cr=(2^8...

If `sum_(r=0)^(10)((r+2)/(r+1)).^n C_r=(2^8-1)/6` , then `n` is (A) 8 (B) 4 (C) 6 (D) 5

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