Show that the equation `e^(sinx)-e^(-sinx)-4=0` has no real solution.

Show that the equation e^(sinx)-e^(-sin x)-4=0 has no real solution.

The equation e^(sinx)-e^(-sinx)-4=0 has (A) non real roots (B) integral roots (C) rational roots (D) real and unequal roots

e^(sinx)sin(e^(x))

The solution of the equation e^(sinx) -e^(-sinx)-4 = 0 is :

The least value of 'a' for which the equation 4/(sinx)+1/(1-sinx)=a has at least one solution in the interval (0,pi//2) , is

The least value of 'a' for which the equation 4/(sinx)+1/(1-sinx)=a has at least one solution in the interval (0,pi//2) , is