Using binomial theorem, expand `{(x+y)^5+(x-y)^5}dot` and hence find the value of `{(sqrt(2)+1)^5+(sqrt(2)-1)^5}dot`

Using binomial theorem,expand {(x+y)^(5)+(x-y)^(5)}* and hence find the value of {(sqrt(2)+1)^(5)+(sqrt(2)-1)^(5)}

Using binomial theorem, expand (x+1/y)^(11)dot

Using binomial theorem, expand [ ( x+y)^(5) + (x-y)^(5) ] and hence find the value of [ ( sqrt(3) + 1)^(5) - ( sqrt(3) - 1)^(5) ] .

Expand (x+y)^(4)-(x-y)^(4) . Hence find the value of (3+sqrt(5))^(4) -(3-sqrt(5))^(4) .

Expand (x+y)^(4)-(x-y)^(4) . Hence find the value of (3+sqrt(5))^(4) -(3-sqrt(5))^(4) .

Using binomial theorem expand (sqrt(x/a)-sqrt(a/x))^6 .

Expand using binomial theorem, (x/3+1/x)^5 .

Find (x+y)^(5)+(x-y)^(5) . Hence evaluate (sqrt(2)+1)^(5)+(sqrt(2)-1)^(5)

Using binomial theorem, expand each of the following: (x-1/y)^(5)