The mean of the series `x_1, x_2,...x_n` is `barX`. If `x_2` is replaced by `lambda` then the new mean is

Statement-1 : The mean of the series x_1, x_2 ,….. x_n is x . If x_2 is replaced by lambda then new mean is independent of lambda Statement-2 : barx (mean)= (x_1+x_2+…. +x_n)/n

Statement-1 : The mean of the series x_1, x_2 ,….. x_n is x. If x_2 is replaced by lambda then new mean is independent of lambda Statement-2 : barx (mean)= (x_1+x_2+…. +x_n)/n

Mean of n observations x_1,x_2 ,…., x_n is barx . If an observation x_q is replaced by x'_q , then the new mean is :

The average of n numbers x_(1),x_(2), …,x_(n) is M. If x_(n) is replaced by x' , then the new average is

The average of n numbers x_(1), x_(2), ….., x_(n) is M. If x_(n) is replaced by x', then new average is :

Mean of n observations x_(1), x_(2), ....,x_(n) is bar(x) . If an observation x_(q) is replaced by x'_(q) then the new mean is

The mean of n observations x_1,x_2,…………..x_n is barx . If (p+q) is added to each observations then prove that the mean of the new set of observations is barx+(p+q) .

Mean of n observations x_(1),x_(2),.......,x_(n) is bar(x) . If an observation x_(q) ' then the new mean is