Convert the following decimal number in the form `p/qdot` `5. bar2` (ii) `23. bar43 `

Explanation

(i) `5. bar2`
`x=5.222....`−(1)
Multiply both side by `10`
`10x=52.222.....`−(2)
Subtract (2) from (1), we get:
`9x=47`
`x=47/9`

`x=23.bar43 .......`-(1)
Multiply both side by `100`
`100x=2343.bar43.....`.-(2)
Subtracting (2) from (1), we get :
`100x-x=2343.bar43−23.bar43`
`99x=2320`
`x=2320/99`