if `costheta=3/5` and `theta` is not in the first quadrant then `(5tan(pi+theta)+4cos(pi+theta))/(5sec(2pi-theta)-4cot(2pi+theta))=`

if cos theta=(3)/(5) and theta is not in the first quadrant then (5tan(pi+theta)+4cos(pi+theta))/(5sec(2 pi-theta)-4cot(2 pi+theta))=

If cos theta =(3)/5 and theta is not in the first quadrant , then (5 tan(pi+ theta ) + 4 cos (pi-theta ))/( 5 sec ( 2pi- theta ) - 4 cot (2pi+ theta ))=

If tan theta = 3/4 and theta is not in the first quadrant then (sin (pi//2 + theta)-cot(pi-theta))/(tan(3 pi//2 - theta)-cos (3pi//2+theta))=

If tan theta=(3)/(4) and theta is not in first quadrant sin(sin((pi)/(2)+theta)-cot(pi-theta))/(tan((3 pi)/(2)-theta)-cos((3 pi)/(2)+theta))=

Prove that (cos(pi +theta)cos (-theta))/(cos(pi-theta) cos (pi/2+theta))=-cot theta

Prove that (cos(pi+theta)cos(-theta))/(cos(pi-theta)cos((pi)/(2)+theta))=-cot theta

Prove that : (cos(pi+theta)cos(-theta))/(sin (pi-theta) cos (pi/2+ theta))= cot^2 theta.

(cosec(2pi+theta)cos(2pi+theta)tan(pi/2+theta))/(sec(pi/2+theta)costhetacot(pi+theta))

If cos theta=-(3)/(5) and pi