Number of terms of an AP is even. The sum of odd terms is 24 an that of even terms is 30. The last term exceeds the first term by `10 1/2`. Find the number of terms.

The number of terms in an A.P. is even , the sum of odd terms is 63 and that of even terms is 72 and the last term exceeds the first term by 16.5 . Find the number of terms :

The number of terms of an A.P. is even, the sum of odd terms is 24, of the even terms is 30, and the last term exceeds the first by 10 1/2 find the number of terms and the series.

The number of terms of an A.P. is even. The sum of the odd terms is 24, and of the even terms is 30, and the last term exceeds the first by 10 1/2 then the number of terms in the series is a. 8 b. 4 c. 6 d. 10

The number of terms of an A.P. is even. The sum of the odd terms is 24, and of the even terms is 30, and the last term exceeds the first by 10 1/2 then the number of terms in the series is a. 8 b. 4 c. 6 d. 10

The number of terms of an A.P. is even, the sum of odd terms is 24, of the even terms is 3, and the last term exceeds the first by 10 1/2 find the number of terms and the series.

The number of terms of an A.P. is even; the sum of the odd terms is 24, and of the even terms is 30, and the last term exceeds the first by 21/2 then the number of terms in the series is 8 b. 4 c. 6 d. 10

The number of terms of an A.P.is even; the sum of the odd terms is 24, and of the even terms is 30 ,and the last term exceeds the first by 10/2 then the number of terms in the series is 8 b.4 c.6 d.10

The number of terms of an A.P. is even the sum of the odd terms is 24 sum of the even terms is 30 and the last term exceeds the first by 10 (1)/(2) then the number of terms in the series is

The number of terms in an AP is even. The sum of the odd terms is 24 while that of the even terms is 30. If the last term exceeds the first by 10.5 then find the number of terms.