If the function `f:[0,8]vecR` is differentiable, then for `0

If the function f : [0,8] to R is differentiable, then for 0 < alpha <1 < beta < 2 , int_0^8 f(t) dt is equal to

If the function f:[0,8]toR is differentiable, then for 0ltalphalt1 and 0lt beta lt 2, int_(0)^(8)f(t)dt is equal to

If the function f:[0,8]toR is differentiable, then for 0ltbetalt1 and 0lt alpha lt 2, int_(0)^(8)f(t)dt is equal to

If the function f:[0,4]vecR is differentiable, the show that for a , b , in (0,4),f^2(4))-(f^2(0))=8f^(prime)(a)f(b)

If the function f:[0,4]vecR is differentiable, the show that for a , b , in (0,4),f(4))^2-(f(0))^2=8f^(prime)(a)f(b)

If the function f:[0,4]vecR is differentiable, the show that for a , b , in (0,4),f^2(4))-(f^2(0))=8f^(prime)(a)f(b)

If the function f:[0,4]->R is differentiable, the show that for a , b , in (0,4),f^2(4) - f^2(0) =8f^(prime)(a)f(b)

If an even function f is differentiable at x=0, then f '(0)=

If f(x)={(x)/(1+e^((1)/(x))) for x!=0,0f or x=0 then the function f(x) is differentiable for

Prove that the function f(x)=|x| is not differentiable there at x=0.