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Prove that:(sinx-sin3x)/(sin^2x-cos^2x)=...

Prove that:`(sinx-sin3x)/(sin^2x-cos^2x)=2sinx`

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To prove that \(\frac{\sin x - \sin 3x}{\sin^2 x - \cos^2 x} = 2 \sin x\), we will start by simplifying the left-hand side (LHS). ### Step 1: Write the LHS \[ \text{LHS} = \frac{\sin x - \sin 3x}{\sin^2 x - \cos^2 x} \] ### Step 2: Simplify the numerator using the sine difference identity ...
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Knowledge Check

  • If [.] denotes the greatest integer functin, then the integral int _(0)^(x//2) (e^(sinx-(sinx))d(sin^(2) x- [sin^(2)x]))/(sin x- [sin x]) is lamda, then [lamda -1] is equal to:

    A
    0
    B
    1
    C
    2
    D
    3
  • If [.] denotes the greatest integer functin, then the integral int _(0)^(x//2) (e^(sinx-(sinx))d(sin^(2) x- [sin^(2)x]))/(sin x- [sin x]) is lamda, then [lamda -1] is equal to:

    A
    0
    B
    1
    C
    2
    D
    3
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