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cos^(2)10^(@)+cos^(3)110^(@)+cos^(3)130^...

cos^(2)10^(@)+cos^(3)110^(@)+cos^(3)130^(@)=sqrt(3)lambda" then "8 lambda=

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cos^(3)110^(@)+cos^(3)10^(@)+cos^(3)130^(@)=

cos^(3)10^(@)+cos^(3)110^(@)+cos^(3)130^(@)=?

8 cos^(3) 10^(@) -6 cos 10^(@) =

cos ^(3) 110 ^(@) + cos ^(3) 10^(@) + cos ^(3) 130^(@)=

cos ^(3) 110 ^(@) + cos ^(3) 10^(@) + cos ^(3) 130^(@)=

If cos48^(0)*cos12^(@)=(sqrt(5)+3)/(lambda) then lambda

cos130^(@)+cos110^(@)+cos10^(@)=0

cos130^(@)+cos110^(@)+cos10^(@)=0

cos48^(0)*cos12^(0)=(sqrt(5)+3)/(lambda) then lambda=

cos170^(@)cos150^(@)cos130^(@)cos110^(@)=