If `f: RR -> RR` is defined by `f(x) = x^2 - 10x + 21` then `f^(-1) (-3)` is 1) {-4,6}2) {2,4}3) {-4,4,64) {4,6}

If f : R to R is defined by f(x) = x^(2)- 6x + 4 then , f(3x + 4) =

If f: [-6, 6] -> RR is defined by f(x)=x^2-3 for x in RR then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

If f: RR -> RR is defined by f(x)={((x-2)/(x^2-3x+2), if x in RR\{1, 2}), (2, if x=1), (1, if x=2):}, then lim_(x->2) (f(x)-f(2))/(x-2)

If f:R-{2/3}rarr R defined by f(x)=(4x+3)/(6x-4) show that f(f(x))=x

If f:[-6, 6]rarr RR defined by f(x)=x^(2)-3" for " x in R then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

Let f , g : RR to RR be defined as f( x) = 2x -|x| and g(x) = 2x+|x|. Find f(g).

If f, RR to RR is defined by f (x) ={{:((x-2)/(x ^(2) -3x+2)"," ,"when " x in RR-{1","2}),(2",","when" x=1),(1",", "when" x=2):} then lim _(xto2) (f(x) -f(2))/(x-2) is equal to-