" If "cos alpha+cos beta=a,sin alpha+sin beta=b" and "alpha-beta=20" then "(cos3 theta)/(cos theta)

Ifcos alpha+cos beta=a,sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+cos beta=a*sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+cos beta=a sin alpha+sin beta=balpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+ cos beta= a, sin alpha+ sin beta= b and alpha- beta= 2 theta . Then (cos 3 theta)/(cos theta)=

If cos a+cos beta=a,sin a+sin beta=b are alpha-beta=2 theta, then (cos3 theta)/(cos3 theta)=

If cos alpha + cos beta = a, sin alpha + sin beta = b and theta is the arithmetic mean between alpha and beta then sin 2 theta + cos 2 theta is equal to

Find the value of, cos alpha cos beta, cos alpha sin beta, -no alpha-sin beta, cos beta, 0 sin alpha cos beta, sin alpha sin beta, cos alpha] |

(cos alpha + cos beta)/( sin alpha - sin beta) + (sin alpha + sin beta)/( cos alpha - cos beta ) =

Evaluate {:[( cos alpha cos beta , cos alpha sin beta , -sin alpha ),( -sin beta , cos beta, 0),( sin alpha cos beta, sin alpha sin beta, cos alpha ) ]:} =0