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If f(x) = 1/2 (3^x + 3^(-x)), g(x) = 1/2...

If `f(x) = 1/2 (3^x + 3^(-x)), g(x) = 1/2 (3^x - 3^(-x))`, then `f(x) \ g(y)+f(y) \ g(x)=`

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