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110.cos^(2)48^(@)-sin^(2)12^(@)" Value o...

110.cos^(2)48^(@)-sin^(2)12^(@)" Value of है- "

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Find the value of (a) sin(pi)/(10).sin(13pi)/(10) (b) cos^(2)48^(@)-sin^(2) 12^(@)

sin 48^(@) * sin 12^(@) =

Find the value of (a) sin(pi)/(10)+sin(13pi)/(10) (b) cos^(2)48^(@)=sin^(2) 12^(@)

cos ^(2) 48^(@) - sin ^(2) 12 ^(@) = (sqrt5+1)/(8).