log_(10)(384)/(5)+log_(10)(81)/(32)+3log_(10)(5)/(3)+log_(10)(1)/(9)

log_(10)3+log_(10)2-2log_(10)5

(log_(10)2)^(3)+log_(10)8*log_(10)5+(log_(10)5)^(3) is

In a binomial distribution B(n,p=(1)/(4)), if the probability of at least one success is greater than or equal to (9)/(10) ,then n is greater than (1)(1)/(log_(10)4)(2)(1)/(log_(10)^(4)+log_(10)^(3))(3)(9)/(log_(10)^(4)-log_(10)^(3))(4)(4)/(log_(10)^(4)-log_(10)^(3))

Givenlog (2)=0.3010 and log_(10)(3)=0.4771 find the value of 7log_(10)((10)/(9))-2log_(10)((25)/(24))+3log_(10)((81)/(80))

(1)/(3)log_(10)125-2log_(10)4+log_(10)32

If log_(10)(2),log_(10)(2^(x)+1),log_(10)(2^(x)-3) are in A.P then x is equal to (i)log_(2)(5)( ii) log_(2)(-1) (iii) log_(2)((1)/(5))( iv) log_(5)(2)

What is the value of log_(10)((9)/(8))-log_(10)((27)/(32))+log_(10)((3)/(4)) ?