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Twenty seven solid iron spheres, each of...

Twenty seven solid iron spheres, each of radius `r` and surface area `S` are melted to form a sphere with surface area `S '` . Find the radius r of the new sphere. ratio of S and S.

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To solve the problem, we need to find the radius \( r' \) of the new sphere formed by melting 27 solid iron spheres, each with radius \( r \), and then determine the ratio of the surface areas \( S \) and \( S' \). ### Step-by-Step Solution: 1. **Surface Area of One Sphere**: The surface area \( S \) of one sphere with radius \( r \) is given by the formula: \[ S = 4\pi r^2 ...
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Twenty-seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S.. Find the (i) radius r. of the new sphere, (ii) ratio of S and S..

Twenty seven solid iron spheres,each of radius r and surface area S are melted to form a sphere with surface area S'. Find the (i) radius r' of the new sphere,(ii) ratio of SandS'.

Knowledge Check

  • Three solid spheres have their radii r_(1),r_(2) and r_(3) .The spheres are melted to form a solid sphere of bigger radius of the new sphere is:

    A
    `(r_(1)+r_(2)+r_(3))`
    B
    `(r_(1)^(2)+r_(2)^(2)+r_(3)^(2))^((1)/(2))`
    C
    `(r_(1)^(3)+r_(2)^(3)+r_(3)^(3))^((1)/(3))`
    D
    `(r_(1)^(4)+r_(2)^(4)+r_(3)^(4))^((1)/(4))`
  • The surface area of a sphere of radius 21 cm is

    A
    `2772 cm^(2)`
    B
    `1386 cm^(2)`
    C
    `4158 cm^(2)`
    D
    `5544 cm^(2)`
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