Length of a class-room is two times its height and its breadth is `1 1/2` times its height. The cost of white-washing the walls at the rate of `R s .1.60 per m^2` is `R s .179.20.` Find the cost of tiling the floor at the rate of `R s .6.75p e rm^2dot`

Explanation

Let height of the room be 'h' m.∴ length of the room=2hm
breadth of the room= 3/2hm
area of '4' walls
='179.20/1.60
=112m^2
2(l+b)×h=112
2(2h+ 3/2h)×h=112
2×7/2×h^2=112
h^2= (112×2)/14
h=16^1/2'
=4m'
length='4×2=8m', breadth= '3/2 ×4=6m'
For,tiling the floor area='l×b=8×6=48m'
Cost of tiling='48×6.75'='Rs324'