If `log_2 (log_3 (log_4 x))= 0, log_4 (log_3 (log_2 y))= 0 and log_3(log_4 (log_2z ))= 0`, then the correct option is

If log_2(log_3(log_4(x)))=0, log_3(log_4(log_2(y)))=0 and log_4(log_2(log_3(z)))=0 then the sum of x,y,z is

Solve : log_4(log_3(log_2x))=0

if log_2(log_3(log_4x))=0 and log_3(log_4(log_2y))=0 and log_3(log_2(log_3z))=0 then find the sum of x, y and z is

if log_(2)(log_(3)(log_(4)x))=0 and log_(3)(log_(4)(log_(2)y))=0 and log_(3)(log_(2)(log_(2)z))=0 then find the sum of x,y and z is

If log_(2)(log_(3)(log_(4)(x)))=0 and log_(3)(log_(4)(log_(2)(y)))=0 and log_(4)(log_(2)(log_(2)(z)))=0 then the sum of x,y and z is _(-)

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is

If log_2 log_3 log_4 (x+1) =0, then x is :-