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Find the particular solution of the differential equation `(dy)/(dx)+ycotx=2x+x^2cotx (x!=0)` given that `y = 0` when `x=pi/2`.

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To find the particular solution of the differential equation \[ \frac{dy}{dx} + y \cot x = 2x + x^2 \cot x \quad (x \neq 0) \] given that \( y = 0 \) when \( x = \frac{\pi}{2} \), we will follow these steps: ...
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Knowledge Check

  • Find the particular solution of the differential equation x(x^(2)-1)(dy)/(dx) =1, it being given that y = 0 when x = 2.

    A
    `y = (1)/(2)log|(4(x^(2)-1))/(x^(2))|,`
    B
    `y = (1)/(2)log|(7(x^(2)-1))/(3x^(2))|,`
    C
    `y = (1)/(2)log|(4(x^(2)-1))/(3x^(2))|,`
    D
    `y = log|(4(x^(2)-1))/(3x^(2))|,`
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